Her goal is to pass a balloon through a small hoop mounted on the observation platform at the top of the Eiffel Tower, 276 m above the ground.

a. If the balloon is to pass through the hoop at the peak of its flight, at what angle above horizontal should she launch the balloon?

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## Answers

Vertical component of velocity = 90 sin θ

Velocity must be 0 at a height of 276m

From v² = u² + 2as, → 0 = u² - 2 · (9.81) · 276

from which u = 73.587

hence 90 sin θ = 73.587

sin θ = 73.587 / 90 = 0.8176

therefore θ = 54.9°

From y = [V*sinΘ]²/(2g) I get

sin²Θ = 2gy/V² = 0.6678 →

Θ = 54.8°