Padhmanban,HowGan

How to integrate (x^2+4x-9/+2)?

sponsored
3 months ago 2

Answers

sponsored
  1. Michael

    Well, we could make the long division
    but we see by looking at the two first terms of the numerator that we can write
    (x^2+4x-9)/(x+2) = (x^2 + 2*2x + 2^2 - 2^2- 9)/(x+2)
    = ( (x+2)^2 - 13)/(x+2) <--- so we obtain the result
    = x+2 - 13/(x+2)
    therefore :
    ∫ (x^2+4x-9)/(x+2) dx = ∫ [ x+2 - 13/(x+2) ] dx = x^2 /2 + 2x - 13 ln( |x+2| ) + C qed hope it' ll help !! PS : welcome to the forum !!
    if you want good answers, don't forget to give BAs too !! ;-)

  2. Como

    Presentation looks dodgy !!!!

Leave A Reply

 Prev Questions

Next Questions